A few more theorems and proofs for your notebook
Isosceles triangle theorem:
If a triangle is isosceles then the angles opposite the congruent sides are congruent.
Proof:
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Bisect ABC with segment BD. ABD@DBC (definition of angle bisector)AB @CB (definition of isosceles triangle)BD @BD (same segment)D ABD@DCBD (side-angle-side postulate) BAD@BCD (definition of congruent triangle)(proven by Jennifer, and Jonathan F. on Nov. 27 Homework) |
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Another Proof:
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Bisect segment AC with segment BD. AD @DC (definition of segment bisector)AB @CB (definition of isosceles triangle)BD @BD (same segment)D ABD@DCBD (side-side-side postulate) BAD@BCD (definition of congruent triangle)(proven by Mark on Nov. 27 Homework) |
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Yet Another Proof:
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AB @CB (definition of isosceles triangle)BC @BA (definition of isosceles triangle)AC @CA (same segment)D ABC@DCBA (side-side-side postulate) BAD@BCD (definition of congruent triangle) |
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Which proof do you like best? Why?
A few more theorems and proofs for your notebook (page 2)
Converse of Isosceles triangle theorem:
If two angles of a triangle are congruent, then the triangle is isosceles and the sides opposite the congruent angles are congruent.
Proof:
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BAC@BCA (given)AC @CA (same segment) ACB@CAB (given)D ABD@DCBD (angle-side-angle postulate)BA @BC (definition of congruent triangle)
(Can you find other proofs?) |
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Triangle midpoint theorem:
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The segments joining the midpoints of the sides of a triangle form four congruent triangles: one using all three segments |
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(See next page for proof)
A few more theorems and proofs for your notebook (page 3)
Proof of Triangle midpoint theorem:
(This is tricky. The idea is to use another figure that we can prove things about, and then prove it is the same figure. Sometimes we only need to add a line or something. Here we need to add a new figure.)
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Draw a figure so that: D ZYX@DABCXW @WZWV is parallel to XY WU is parallel to ZY WXU@ZWV(corr. angles) WX @ZW (given) XWU@WZV(corr. angles) D WXU@DZWV (angle-side-angle postulate)XU @WV(definition of congruent triangles) |
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XUW@VWU (alternate angles)UW
@WU (same segment)D
XUW@DVWU (side-angle-side postulate)m
XUW+mWUV+mVUY=180°ree; (on a straight line, angle addition postulate)
XWU@WUV (alternate angles, or definition of congruent triangles)m
XUW+mXWU+mVUY=180°ree; (substitution of equals)m
XUW+mXWU+mUXW=180°ree; (angle sum of triangle = 180°ree;)
YUV@UXW (transitive, subtraction, etc.)
VYU@WUX (Corresponding angles)XW
@UV (definition of congruent triangles)D
UXW@DYUV (angle-angle-side theorem)(continued)
A few more theorems and proofs for your notebook (page 4)
Proof of Triangle midpoint theorem (continued)
XU
@UY (definition of congruent triangles)ZV
@VY (definition of congruent triangles)
ACB@ZXY (definition of congruent triangles)AC
@ZX (definition of congruent triangles)DC
@WX (both are half of congruent segments)BC
@YX (definition of congruent triangles)FC
@UX (both are half of congruent segments)D
DCF@DWXU (side-angle-side postulate)D
AED@DZVW (same reasoning as DDCF@DWXU)D
EBF@DVYU (same reasoning as DDCF@DWXU)DE
@WV (definition of congruent triangles)EF
@VU (definition of congruent triangles)FD
@UW (definition of congruent triangles)D
DEF@DWVU (side-side-side postulate)D
UXW@DYUV (from above)D
DCF@DWXU (from above)D
EBF@DVYU (from above)D
EBF@DDFC (transitive postulate)D
XUW@DVWU (from above)D
DEF@DWVU (from above)D
DCF@DWXU (from above)D
DCF@DFED (transitive postulate)D
AED@DDFC (by the same reasoning)QED (an abbreviation for quod erat demonstrandum, which means "What we had to prove is proven.")